Next: B. Proofs of Some
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A. Hints and Answers
- Exercise 0.3:
- The Rhind value is
- Exercise 1.7:
- Look at the boundary.
- Exercise 1.10:
- If a set has no endpoints, then it contains all of its endpoints and none of its endpoints.
- Exercise 2.10:
-
- Exercise 2.18:
- area
.
- Exercise 2.27:
-
.
- Exercise 2.36:
- I let
and
.
- Exercise 3.20:
- Recall
or not .
- Exercise 5.61:
-
. (Draw a picture.)
- Exercise 5.80:
- Consider a partition with a fairly large number of points.
- Exercise 6.33:
- The assertion is false.
- Exercise 6.59:
- (part e) The limit is . It simplifies matters if you factor both the numerator and the denominator. The sequence in part g) is a translate of the sequence in part f).
- Exercise 6.69:
- All four statements are false.
- Exercise 6.94:
- a)
.
- Exercise 6.97:
-
.
- Exercise 7.16:
- Take
in lemma 7.13.
- Exercise 7.18:
-
. Show that
is small when is large.
- Exercise 8.14:
-
. Not all of these integrals exist.
- Exercise 8.16:
- Show that
for every partition of and every sample for .
- Exercise 8.28:
- is the sum of an integrable function and a spike function.
- Exercise 8.32:
- is not piecewise monotonic. It is easy to see that is integrable on . If you can show it is integrable on then you are essentially done.
- Exercise 8.34:
- b) .
- Exercise 8.41:
- For any partition of you can find a sample such that
- Exercise 8.46:
- In equation 8.44, replace by , , and replace and by and .
- Exercise 8.48:
-
- Exercise 8.50:
- If then both areas are approximately 3.1416
- Exercise 8.55:
- area = .
- Exercise 8.57:
- The areas are and .
- Exercise 8.58:
- The area is . Some fractions with large numerators may appear along the way.
- Exercise 9.20:
- The last two formulas are obtained from the second by replacing by .
- Exercise 9.29:
- I used exercise 9.28 with
to find
. You can also give a more geometric proof.
- Exercise 9.44:
- You will need to use (9.24).
- Exercise 9.48:
-
.
- Exercise 9.49:
- area .
- Exercise 9.69:
-
- Exercise 10.25:
-
- Exercise 10.26:
- See example 10.9 and 9.26.
- Exercise 10.27:
-
- Exercise 10.28:
-
- Exercise 11.6:
- I used formula 9.25
- Exercise 11.15:
-
- Exercise 11.21:
- You can use the definition of derivative, or you can use the product rule and the reciprocal rule.
- Exercise 11.24:
-
,
,
- Exercise 11.29:
-
for
. If you said
, calculate both sides when .
- Exercise 11.40:
- Use the definition of derivative. .
- Exercise 11.43:
-
,
,
,
,
,
(It requires a lot of calculation to simplify ),
,
- Exercise 12.14:
- d) Such a function does exist.
- Exercise 12.15:
- a) Use extreme value property.
- Exercise 12.27:
- Proof is like given proof of corollary 12.26.
- Exercise 12.31:
- Apply corollary 12.26 to .
- Exercise 12.35:
- Yes.
- Exercise 12.36:
- You can apply the chain rule to the identity .
- Exercise 13.14:
- The function to minimize is distance
.
- Exercise 13.15:
- You may get a complicated equation of the form
to solve. Square both sides and the equation should simplify.
- Exercise 14.5:
- Apply the intermediate value property to .
- Exercise 14.9:
- One of the zeros is in .
- Exercise 14.10:
- I showed that if temp temp temp, then there is a point in such that temp temp.
- Exercise 14.11:
- if temp temp temp temp, find two points different from that have the same temperature as .
- Exercise 14.17:
- You may want to define some of these functions using more than one formula.
- Exercise 14.41:
- Use the extreme value property to get and .
- Exercise 14.54:
-
;
;
;
.
- Exercise 14.55:
- It is not true that for all . Note that the image of is
.
- Exercise 15.5:
-
.
- Exercise 15.8:
- Use the antiderivative theorem twice.
- Exercise 15.9:
-
.
- Exercise 15.13:
- You will need to use a few trigonometric identities, including the reflection law (9.18).
- Exercise 15.22:
-
- Exercise 15.29:
- Use theorem 15.27 and corollary 12.26
- Exercise 16.2:
- You probably will not be able to find a ``single formula'' for this. My function has a local maximum at
for all
.
- Exercise 16.8:
- The result is known if . To get the result when , apply 16.6 to on .
- Exercise 16.13:
- Not all of these integrals make sense. for all
. for
. for
. is not defined.
- Exercise 17.16:
- b)
; f)
. i) Cf example 9.68i.j) You did this in exercise 9.69.
- Exercise 17.31:
- b)
When you do the second integration by parts, be careful not to undo the first. c)
. Let . d) and e) can be done easily without using integration by parts. f) If the answer is
.
- Exercise 17.42:
- c) Let . You will need an integration by parts. d) Let . e) Remember the definition of .
- Exercise 17.49:
- a)
If you forget how to find
, review example 9.53. Also recall that
. b)
c) and d) do not require a trigonometric substitution.
- Exercise 17.53:
- a) b)
c)
- Exercise 17.54:
-
- Exercise 17.64:
- (g)
First complete the square, and then reduce the problem to
.
Next: B. Proofs of Some
Up: Math 111 Calculus I
Previous: Bibliography
  Index
Ray Mayer
2007-09-07