Next: B. Proofs of Some
 Up: Math 111 Calculus I
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     Index 
A. Hints and Answers
- Exercise 0.3:
 
- The Rhind value is 
 
- Exercise 1.7:
 
- Look at the boundary.
 
- Exercise 1.10:
 
- If a set has no endpoints, then it contains all of its endpoints and none of its endpoints.
 
- Exercise 2.10:
 
- 
 
- Exercise 2.18:
 
- area
.
 
- Exercise 2.27:
 
- 
.
 
- Exercise 2.36:
 
- I let 
 and 
.
 
- Exercise 3.20:
 
- Recall 
 or not 
.
 
- Exercise 5.61:
 
- 
. (Draw a picture.)
 
- Exercise 5.80:
 
- Consider a partition with a fairly large number of points.
 
- Exercise 6.33:
 
- The assertion is false.
 
- Exercise 6.59:
 
- (part e) The limit is 
. It simplifies matters if you factor both the numerator and the denominator. The sequence in part g) is a translate of the sequence in part f).
 
- Exercise 6.69:
 
- All four statements are false.
 
- Exercise 6.94:
 
- a) 
.
 
- Exercise 6.97:
 
- 
.
 
- Exercise 7.16:
 
- Take 
 in lemma 7.13.
 
- Exercise 7.18:
 
- 
. Show that 
 is small when 
 is large.
 
- Exercise 8.14:
 
- 
.  Not all of these integrals exist.
 
- Exercise 8.16:
 
- Show that 
 for every partition 
 of 
 and every sample 
 for 
.
 
- Exercise 8.28:
 
 is the sum of an integrable function and a spike function.
 
- Exercise 8.32:
 
 is not piecewise monotonic. It is easy to see that 
 is integrable on 
. If you can show it is integrable on 
then you are essentially done.
 
- Exercise 8.34:
 
- b) 
. 
 
- Exercise 8.41:
 
- For any partition 
 of 
 you can find a sample 
 such that 
 
- Exercise 8.46:
 
- In equation 8.44, replace 
 by 
, , and replace 
 and 
 by 
 and 
.
 
- Exercise 8.48:
 
- 
 
- Exercise 8.50:
 
- If 
 then both areas are approximately 3.1416
 
- Exercise 8.55:
 
- area = 
.
 
- Exercise 8.57:
 
- The areas are 
 and 
.
 
- Exercise 8.58:
 
- The area is 
. Some fractions with large numerators may appear along the way.
 
- Exercise 9.20:
 
- The last two formulas are obtained from the second by replacing 
 by 
.
 
- Exercise 9.29:
 
- I used exercise 9.28 with 
 to find 
. You can also give a more geometric proof.
 
- Exercise 9.44:
 
- You will need to use (9.24).
 
- Exercise 9.48:
 
- 
.
 
- Exercise 9.49:
 
- area 
.
 
- Exercise 9.69:
 
- 
 
 
 
- Exercise 10.25:
 
- 
 
- Exercise 10.26:
 
- See example 10.9 and 9.26.
 
- Exercise 10.27:
 
- 
 
- Exercise 10.28:
 
 
 
- Exercise 11.6:
 
- I used formula 9.25
 
- Exercise 11.15:
 
- 
 
- Exercise 11.21:
 
- You can use the definition of derivative, or you can use the product rule and the reciprocal rule.
 
- Exercise 11.24:
 
- 
, 
, 
 
- Exercise 11.29:
 
- 
 for 
. If you said 
, calculate both sides when 
.
 
- Exercise 11.40:
 
- Use the definition of derivative. 
.
 
- Exercise 11.43:
 
- 
, 
, 
, 
, 
, 
 (It requires a lot of calculation to simplify 
), 
, 
 
- Exercise 12.14:
 
- d) Such a function 
 does exist.
 
- Exercise 12.15:
 
- a) Use extreme value property.
 
- Exercise 12.27:
 
- Proof is like given proof of corollary 12.26.
 
- Exercise 12.31:
 
- Apply corollary 12.26 to 
.
 
- Exercise 12.35:
 
- Yes.
 
- Exercise 12.36:
 
- You can apply the chain rule to the identity 
.
 
- Exercise 13.14:
 
- The function to minimize is 
distance
.
 
- Exercise 13.15:
 
- You may get a complicated equation of the form 
 to solve. Square both sides and the equation should simplify.
 
- Exercise 14.5:
 
- Apply the intermediate value property to 
.
 
- Exercise 14.9:
 
- One of the zeros is in 
.
 
- Exercise 14.10:
 
- I showed that if temp
 temp
 temp
, then there is a point 
 in 
 such that temp
 temp
.
 
- Exercise 14.11:
 
- if temp
 temp
 temp
 temp
, find two points different from 
 that have the same temperature as 
.
 
- Exercise 14.17:
 
- You may want to define some of these functions using more than one formula.
 
- Exercise 14.41:
 
- Use the extreme value property to get 
 and 
.
 
- Exercise 14.54:
 
- 
; 
; 
; 
.
 
- Exercise 14.55:
 
- It is not true that 
 for all 
. Note that the image of 
 is 
.
 
- Exercise 15.5:
 
- 
.
 
- Exercise 15.8:
 
- Use the antiderivative theorem twice.
 
- Exercise 15.9:
 
- 
.
 
- Exercise 15.13:
 
- You will need to use a few trigonometric identities, including the reflection law (9.18).
 
- Exercise 15.22:
 
- 
 
- Exercise 15.29:
 
- Use theorem 15.27 and corollary 12.26
 
- Exercise 16.2:
 
- You probably will not be able to find a ``single formula'' for this. My function has a local maximum at 
 for all 
.
 
- Exercise 16.8:
 
- The result is known if 
. To get the result when 
, apply 16.6 to 
 on 
.
 
- Exercise 16.13:
 
- Not all of these integrals make sense. 
 for all 
. 
 for 
. 
 for 
. 
 is not defined.
 
- Exercise 17.16:
 
- b) 
; f) 
.  i) Cf example 9.68i.j) You did this in exercise 9.69.
 
- Exercise 17.31:
 
- b) 
 When you do the second integration by parts, be careful not to undo the first. c) 
. Let 
. d) and e) can be done easily without using integration by parts. f) If 
 the answer is 
.
 
- Exercise 17.42:
 
- c) Let 
. You will need an integration by parts. d) Let 
. e) Remember the definition of 
. 
 
- Exercise 17.49:
 
- a) 
 If you forget how to find 
, review example 9.53. Also recall that 
. b) 
 c) and d) do not require a trigonometric substitution.
 
- Exercise 17.53:
 
- a) 
 b) 
 c)
 
- Exercise 17.54:
 
- 
 
- Exercise 17.64:
 
- (g) 
 First complete the square, and then reduce the problem to 
.
 
 
 
  
 
 Next: B. Proofs of Some
 Up: Math 111 Calculus I
 Previous: Bibliography
     Index 
Ray Mayer
2007-09-07