| Let T be a linear operator on a finite dimensional vector
space V and let n be an integer >1. This talk is concerned with the
question "Does T have an n-th root?" i.e., is there a linear operator
U on V such that U^n (U composed with itself n times) is equal to T?
In this talk, I will describe an algorithm to find all such U which
can be expressed as polynomials in T. |